What is the general solution for -7cos(7x)=0 ?

The general solution for -7cos(7x)=0 is x= pi/(14)+(2pin)/7 ,x=(3pi}{14}+\frac{2pin)/7

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-7cos(7x)=0

- 7 cos (7 x) = 0

x = \frac{π}{14} + \frac{2 πn}{7}, x = \frac{3 π}{14} + \frac{2 πn}{7}

Solution steps

- 7 cos (7 x) = 0

Divide both sides by

- 7

cos (7 x) = 0

General solutions for

cos (7 x) = 0

7 x = \frac{π}{2} + 2 πn, 7 x = \frac{3 π}{2} + 2 πn

Solve

7 x = \frac{π}{2} + 2 πn : x = \frac{π}{14} + \frac{2 πn}{7}

Solve

7 x = \frac{3 π}{2} + 2 πn : x = \frac{3 π}{14} + \frac{2 πn}{7}

x = \frac{π}{14} + \frac{2 πn}{7}, x = \frac{3 π}{14} + \frac{2 πn}{7}

1 - 4 sin^{2} (x) = 0

cos (2 θ) - 6 sin^{2} (θ) = - 5

sin (A) = \frac{15}{17}

9 sin (x) = 0

cos (θ) = \frac{20}{25}

What is the general solution for -7cos(7x)=0 ?
The general solution for -7cos(7x)=0 is x= pi/(14)+(2pin)/7 ,x=(3pi}{14}+\frac{2pin)/7