What is the general solution for 2cos^2(x)+sin^2(x)=2 ?

The general solution for 2cos^2(x)+sin^2(x)=2 is x=2pin,x=pi+2pin

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2cos^2(x)+sin^2(x)=2

2 cos^{2} (x) + sin^{2} (x) = 2

x = 2 πn, x = π + 2 πn

Solution steps

2 cos^{2} (x) + sin^{2} (x) = 2

Subtract

2

from both sides

2 cos^{2} (x) + sin^{2} (x) - 2 = 0

Rewrite using trig identities

- sin^{2} (x) = 0

Divide both sides by

- 1

sin (x) = 0

General solutions for

sin (x) = 0

x = 0 + 2 πn, x = π + 2 πn

Solve

x = 0 + 2 πn : x = 2 πn

x = 2 πn, x = π + 2 πn

2 cos^{2} (x) + sin^{2} (x) = 0

9.383 = 3.1915 cos (\frac{π}{6 ( 1 - c )}) + 6.1915

tan (2 x) = - \frac{40}{3}

3 cos (2 x) - 5 sin (x) + 1 = 0

tan (θ) = \frac{5}{- 2}

What is the general solution for 2cos^2(x)+sin^2(x)=2 ?
The general solution for 2cos^2(x)+sin^2(x)=2 is x=2pin,x=pi+2pin