What is the general solution for 8cos(x)+4=0 ?

The general solution for 8cos(x)+4=0 is x=(2pi)/3+2pin,x=(4pi)/3+2pin

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8cos(x)+4=0

8 cos (x) + 4 = 0

x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn

Solution steps

8 cos (x) + 4 = 0

Move

4

to the right side

8 cos (x) = - 4

Divide both sides by

8

cos (x) = - \frac{1}{2}

General solutions for

cos (x) = - \frac{1}{2}

x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn

6 = 6 (1 - sin (θ))

tan (x) = 3, - π \leq x < π

4 cos (x) - 4 sin (x) = 0

3 csc (3 x) = - 2

2 cos (2 θ) + 1 = - 12 cos (θ) - 6

What is the general solution for 8cos(x)+4=0 ?
The general solution for 8cos(x)+4=0 is x=(2pi)/3+2pin,x=(4pi)/3+2pin