What is the general solution for 2cos(x)=1,0,360 ?

The general solution for 2cos(x)=1,0,360 is No Solution for x\in\mathbb{R}

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2cos(x)=1,0,360

2 cos (x) = 1, 0, 36 0^{\circ}

No Solution for x \in R

Solution steps

2 cos (x) = 1, 0, 36 0^{\circ}

Divide both sides by

2

cos (x) = \frac{1}{2}

General solutions for

cos (x) = \frac{1}{2}

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

Solutions for the range

0

No Solution for x \in R

cot^{2} (x) - csc (x) - 1 = 0

16 sin^{4} (θ) - 16 sin^{2} (θ) + 3 = 0

7 sin (\frac{θ}{2}) = - 7 cos (\frac{θ}{2})

p, e^{x} - sin (p \frac{x}{3}) = 0

2 cos (x) + cos (2 x) \cdot 2 = 0

What is the general solution for 2cos(x)=1,0,360 ?
The general solution for 2cos(x)=1,0,360 is No Solution for x\in\mathbb{R}