What is the general solution for cos(θ)= 6/(sqrt(14)*\sqrt{9)} ?

The general solution for cos(θ)= 6/(sqrt(14)*\sqrt{9)} is θ=1.00685…+2pin,θ=2pi-1.00685…+2pin

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cos(θ)= 6/(sqrt(14)*\sqrt{9)}

cos (θ) = \frac{6}{14 \cdot 9}

θ = 1.00685 \dots + 2 πn, θ = 2 π - 1.00685 \dots + 2 πn

Solution steps

cos (θ) = \frac{6}{14 9}

Simplify

\frac{6}{14 9} : \frac{2}{7}

Apply trig inverse properties

θ = arccos (\frac{2}{7}) + 2 πn, θ = 2 π - arccos (\frac{2}{7}) + 2 πn

Show solutions in decimal form

θ = 1.00685 \dots + 2 πn, θ = 2 π - 1.00685 \dots + 2 πn

sin (θ + \frac{π}{4}) = \frac{1}{2}

(cot (x) - 1) (sin (x) - 1) = 0

x, sin (y) + cos (x) = 1

x, u = cos (x)

tan (x) + 1 = \frac{1}{5}

What is the general solution for cos(θ)= 6/(sqrt(14)*\sqrt{9)} ?
The general solution for cos(θ)= 6/(sqrt(14)*\sqrt{9)} is θ=1.00685…+2pin,θ=2pi-1.00685…+2pin