What is the general solution for (cot(x)-1)(sin(x)-1)=0 ?

The general solution for (cot(x)-1)(sin(x)-1)=0 is x= pi/4+pin,x= pi/2+2pin

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(cot(x)-1)(sin(x)-1)=0

(cot (x) - 1) (sin (x) - 1) = 0

x = \frac{π}{4} + πn, x = \frac{π}{2} + 2 πn

Solution steps

(cot (x) - 1) (sin (x) - 1) = 0

Solving each part separately

cot (x) - 1 = 0 or sin (x) - 1 = 0

cot (x) - 1 = 0 : x = \frac{π}{4} + πn

sin (x) - 1 = 0 : x = \frac{π}{2} + 2 πn

Combine all the solutions

x = \frac{π}{4} + πn, x = \frac{π}{2} + 2 πn

x, sin (y) + cos (x) = 1

x, u = cos (x)

tan (x) + 1 = \frac{1}{5}

cos (2 x) = \frac{119}{169}

x, 2 cos (x) - 1 = 0

What is the general solution for (cot(x)-1)(sin(x)-1)=0 ?
The general solution for (cot(x)-1)(sin(x)-1)=0 is x= pi/4+pin,x= pi/2+2pin