What is the general solution for cos(2x)= 119/169 ?

The general solution for cos(2x)= 119/169 is x=(0.78958…)/2+pin,x=pi-(0.78958…)/2+pin

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cos(2x)= 119/169

cos (2 x) = \frac{119}{169}

x = \frac{0.78958 \dots}{2} + πn, x = π - \frac{0.78958 \dots}{2} + πn

Solution steps

cos (2 x) = \frac{119}{169}

Apply trig inverse properties

2 x = arccos (\frac{119}{169}) + 2 πn, 2 x = 2 π - arccos (\frac{119}{169}) + 2 πn

Solve

2 x = arccos (\frac{119}{169}) + 2 πn : x = \frac{arccos ( \frac{119}{169} )}{2} + πn

Solve

2 x = 2 π - arccos (\frac{119}{169}) + 2 πn : x = π - \frac{arccos ( \frac{119}{169} )}{2} + πn

x = \frac{arccos ( \frac{119}{169} )}{2} + πn, x = π - \frac{arccos ( \frac{119}{169} )}{2} + πn

Show solutions in decimal form

x = \frac{0.78958 \dots}{2} + πn, x = π - \frac{0.78958 \dots}{2} + πn

x, 2 cos (x) - 1 = 0

2 sin (2 x) = - 2

tan^{4} (x) + 2 tan^{2} (x) - 7 = 0

cos (x) = 2 + 3 sin (x)

tan^{2} (θ) + 4 tan (θ) = 0

What is the general solution for cos(2x)= 119/169 ?
The general solution for cos(2x)= 119/169 is x=(0.78958…)/2+pin,x=pi-(0.78958…)/2+pin