What is the general solution for cos(4x+4)=sin(10x+44) ?

The general solution for cos(4x+4)=sin(10x+44) is x=(4pin+pi-96)/(28),x=(pi+4pin-80)/(12)

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cos(4x+4)=sin(10x+44)

cos (4 x + 4) = sin (10 x + 44)

x = \frac{4 πn + π - 96}{28}, x = \frac{π + 4 πn - 80}{12}

Solution steps

cos (4 x + 4) = sin (10 x + 44)

Rewrite using trig identities

cos (4 x + 4) = sin (\frac{π}{2} - (4 x + 4))

Apply trig inverse properties

10 x + 44 = \frac{π}{2} - (4 x + 4) + 2 πn, 10 x + 44 = π - (\frac{π}{2} - (4 x + 4)) + 2 πn

10 x + 44 = \frac{π}{2} - (4 x + 4) + 2 πn : x = \frac{4 πn + π - 96}{28}

10 x + 44 = π - (\frac{π}{2} - (4 x + 4)) + 2 πn : x = \frac{π + 4 πn - 80}{12}

x = \frac{4 πn + π - 96}{28}, x = \frac{π + 4 πn - 80}{12}

4 tan^{2} (x) - 3 sec^{2} (x) = 0

(sin (t) - 1) cos (t) = 0

csc (x) = 1, 0 \leq x \leq 2 π

4 sin (θ) + 33 = 3

cos (2 x) - 2 sin (x) = 0

What is the general solution for cos(4x+4)=sin(10x+44) ?
The general solution for cos(4x+4)=sin(10x+44) is x=(4pin+pi-96)/(28),x=(pi+4pin-80)/(12)