What is the general solution for sin(θ)=-24/25 ,pi<θ<(3pi)/2 ?

The general solution for sin(θ)=-24/25 ,pi<θ<(3pi)/2 is θ=pi+1.28700…

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(θ)=-24/25 ,pi<θ<(3pi)/2

sin (θ) = - \frac{24}{25}, π < θ < \frac{3 π}{2}

θ = π + 1.28700 \dots

Solution steps

sin (θ) = - \frac{24}{25}, π < θ < \frac{3 π}{2}

Apply trig inverse properties

θ = arcsin (- \frac{24}{25}) + 2 πn, θ = π + arcsin (\frac{24}{25}) + 2 πn

Solutions for the range

π < θ < \frac{3 π}{2}

θ = π + arcsin (\frac{24}{25})

Show solutions in decimal form

θ = π + 1.28700 \dots

sin (\frac{2 θ}{3}) = 0

3 sec^{2} (x) - 6 = 0

sin (x) = \frac{6}{19}

- 2 sin (x) cos (x) + 3 cos (x) = sin (x) + 3 cos (x)

4 sin^{2} (x) - 4 cos^{2} (x) = 23

What is the general solution for sin(θ)=-24/25 ,pi<θ<(3pi)/2 ?
The general solution for sin(θ)=-24/25 ,pi<θ<(3pi)/2 is θ=pi+1.28700…