What is the general solution for 5sin(x)+3=2 ?

The general solution for 5sin(x)+3=2 is x=-0.20135…+2pin,x=pi+0.20135…+2pin

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5sin(x)+3=2

5 sin (x) + 3 = 2

x = - 0.20135 \dots + 2 πn, x = π + 0.20135 \dots + 2 πn

Solution steps

5 sin (x) + 3 = 2

Move

3

to the right side

5 sin (x) = - 1

Divide both sides by

5

sin (x) = - \frac{1}{5}

Apply trig inverse properties

x = arcsin (- \frac{1}{5}) + 2 πn, x = π + arcsin (\frac{1}{5}) + 2 πn

Show solutions in decimal form

x = - 0.20135 \dots + 2 πn, x = π + 0.20135 \dots + 2 πn

17 arccos (x) - 4 π = arccos (x)

cos (6 x) - cos (3 x) = 0

sin (4 θ) = - \frac{1}{2}

cos (x) = \frac{3}{4}

cos^{2} (x) + \frac{3}{2} sin (2 x) = 0

What is the general solution for 5sin(x)+3=2 ?
The general solution for 5sin(x)+3=2 is x=-0.20135…+2pin,x=pi+0.20135…+2pin