What is the general solution for 3cos(3θ)=0 ?

The general solution for 3cos(3θ)=0 is θ= pi/6+(2pin)/3 ,θ= pi/2+(2pin)/3

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3cos(3θ)=0

3 cos (3 θ) = 0

θ = \frac{π}{6} + \frac{2 πn}{3}, θ = \frac{π}{2} + \frac{2 πn}{3}

Solution steps

3 cos (3 θ) = 0

Divide both sides by

3

cos (3 θ) = 0

General solutions for

cos (3 θ) = 0

3 θ = \frac{π}{2} + 2 πn, 3 θ = \frac{3 π}{2} + 2 πn

Solve

3 θ = \frac{π}{2} + 2 πn : θ = \frac{π}{6} + \frac{2 πn}{3}

Solve

3 θ = \frac{3 π}{2} + 2 πn : θ = \frac{π}{2} + \frac{2 πn}{3}

θ = \frac{π}{6} + \frac{2 πn}{3}, θ = \frac{π}{2} + \frac{2 πn}{3}

3 cot (\frac{π}{2} x) = - 3

0 = 3.46 sin (x) - 704.35

cos (θ) = \frac{3}{5}, \frac{3 π}{2} < θ < 2 π

cos (2 x) = \frac{3}{2}

- 3 cos (2 θ) + 2 sin (θ) + 5 = 9 sin (θ)

What is the general solution for 3cos(3θ)=0 ?
The general solution for 3cos(3θ)=0 is θ= pi/6+(2pin)/3 ,θ= pi/2+(2pin)/3