What is the general solution for 2cos^2(x)+3cos(x)-2=0,-pi<= x<= pi ?

The general solution for 2cos^2(x)+3cos(x)-2=0,-pi<= x<= pi is x= pi/3 ,x=-pi/3

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2cos^2(x)+3cos(x)-2=0,-pi<= x<= pi

2 cos^{2} (x) + 3 cos (x) - 2 = 0, - π \leq x \leq π

x = \frac{π}{3}, x = - \frac{π}{3}

Solution steps

2 cos^{2} (x) + 3 cos (x) - 2 = 0, - π \leq x \leq π

Solve by substitution

cos (x) = \frac{1}{2}, cos (x) = - 2

cos (x) = \frac{1}{2}, - π \leq x \leq π : x = \frac{π}{3}, x = - \frac{π}{3}

cos (x) = - 2, - π \leq x \leq π :

No Solution

Combine all the solutions

x = \frac{π}{3}, x = - \frac{π}{3}

- 5 cos (x) + 8.6602500000000 \dots sin (x) = - 5

sin (2 π \cdot 1.5 x) = 0

sin (15 x) + cos (15 x) = 0

1 + 2 sin (\frac{t ^{2}}{2}) = 0

3 tan^{2} (x) - 2 = csc^{2} (x) - cot^{2} (x)

What is the general solution for 2cos^2(x)+3cos(x)-2=0,-pi<= x<= pi ?
The general solution for 2cos^2(x)+3cos(x)-2=0,-pi<= x<= pi is x= pi/3 ,x=-pi/3