What is the general solution for 8cos(x)-4=0 ?

The general solution for 8cos(x)-4=0 is x= pi/3+2pin,x=(5pi)/3+2pin

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8cos(x)-4=0

8 cos (x) - 4 = 0

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

Solution steps

8 cos (x) - 4 = 0

Move

4

to the right side

8 cos (x) = 4

Divide both sides by

8

cos (x) = \frac{1}{2}

General solutions for

cos (x) = \frac{1}{2}

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

sin^{2} (θ) = 5 sin (θ) + 6

2 = 2 sec (x)

cos (x) - sin (x) = \frac{2}{2}

cos^{2} (θ) = 1 + sin (θ)

\frac{2}{5} cos (x) = \frac{2}{5}

What is the general solution for 8cos(x)-4=0 ?
The general solution for 8cos(x)-4=0 is x= pi/3+2pin,x=(5pi)/3+2pin