What is the general solution for -2sin(θ)(1+cos(θ))=0 ?

The general solution for -2sin(θ)(1+cos(θ))=0 is θ=2pin,θ=pi+2pin

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-2sin(θ)(1+cos(θ))=0

- 2 sin (θ) (1 + cos (θ)) = 0

θ = 2 πn, θ = π + 2 πn

Solution steps

- 2 sin (θ) (1 + cos (θ)) = 0

Solving each part separately

sin (θ) = 0 or 1 + cos (θ) = 0

sin (θ) = 0 : θ = 2 πn, θ = π + 2 πn

1 + cos (θ) = 0 : θ = π + 2 πn

Combine all the solutions

θ = 2 πn, θ = π + 2 πn

2 sec^{2} (2 x) = 3 tan (2 x) + 1

4 cot (x) + 5 = 9

2 = \frac{1}{2} [1 + arctan (\frac{1}{1 + C})]

x, tan (x) = \frac{1}{2}

t, x = sin^{2} (t)

What is the general solution for -2sin(θ)(1+cos(θ))=0 ?
The general solution for -2sin(θ)(1+cos(θ))=0 is θ=2pin,θ=pi+2pin