What is the general solution for -tan^2(x)-2tan(x)-1=0 ?

The general solution for -tan^2(x)-2tan(x)-1=0 is x=(3pi)/4+pin

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-tan^2(x)-2tan(x)-1=0

- tan^{2} (x) - 2 tan (x) - 1 = 0

x = \frac{3 π}{4} + πn

Solution steps

- tan^{2} (x) - 2 tan (x) - 1 = 0

Solve by substitution

tan (x) = - 1

tan (x) = - 1 : x = \frac{3 π}{4} + πn

Combine all the solutions

x = \frac{3 π}{4} + πn

sin (x) = \frac{4}{6 2}

cos (5 x) = cos (3 x)

2 cos (2 t) = 0

4 cos^{2} (θ) = 3 + 3 sin (θ)

4 cos (3 θ) + 23 = 0

What is the general solution for -tan^2(x)-2tan(x)-1=0 ?
The general solution for -tan^2(x)-2tan(x)-1=0 is x=(3pi)/4+pin