What is the general solution for 2cos(2t)=0 ?

The general solution for 2cos(2t)=0 is t= pi/4+pin,t=(3pi)/4+pin

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Popular Trigonometry >

2cos(2t)=0

Solution

2 cos (2 t) = 0

Solution

t = \frac{π}{4} + πn, t = \frac{3 π}{4} + πn

Degrees

t = 4 5^{\circ} + 18 0^{\circ} n, t = 13 5^{\circ} + 18 0^{\circ} n

Solution steps

2 cos (2 t) = 0

Divide both sides by

2

2 cos (2 t) = 0

Divide both sides by

2

\frac{2 cos ( 2 t )}{2} = \frac{0}{2}

Simplify

cos (2 t) = 0

cos (2 t) = 0

General solutions for

cos (2 t) = 0

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

2 t = \frac{π}{2} + 2 πn, 2 t = \frac{3 π}{2} + 2 πn

2 t = \frac{π}{2} + 2 πn, 2 t = \frac{3 π}{2} + 2 πn

Solve

2 t = \frac{π}{2} + 2 πn : t = \frac{π}{4} + πn

2 t = \frac{π}{2} + 2 πn

Divide both sides by

2

2 t = \frac{π}{2} + 2 πn

Divide both sides by

2

\frac{2 t}{2} = \frac{\frac{π}{2}}{2} + \frac{2 πn}{2}

Simplify

\frac{2 t}{2} = \frac{\frac{π}{2}}{2} + \frac{2 πn}{2}

Simplify

\frac{2 t}{2} : t

\frac{2 t}{2}

Divide the numbers:

\frac{2}{2} = 1

= t

Simplify

\frac{\frac{π}{2}}{2} + \frac{2 πn}{2} : \frac{π}{4} + πn

\frac{\frac{π}{2}}{2} + \frac{2 πn}{2}

\frac{\frac{π}{2}}{2} = \frac{π}{4}

\frac{\frac{π}{2}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{π}{2 \cdot 2}

Multiply the numbers:

2 \cdot 2 = 4

= \frac{π}{4}

\frac{2 πn}{2} = πn

\frac{2 πn}{2}

Divide the numbers:

\frac{2}{2} = 1

= πn

= \frac{π}{4} + πn

t = \frac{π}{4} + πn

t = \frac{π}{4} + πn

t = \frac{π}{4} + πn

Solve

2 t = \frac{3 π}{2} + 2 πn : t = \frac{3 π}{4} + πn

2 t = \frac{3 π}{2} + 2 πn

Divide both sides by

2

2 t = \frac{3 π}{2} + 2 πn

Divide both sides by

2

\frac{2 t}{2} = \frac{\frac{3 π}{2}}{2} + \frac{2 πn}{2}

Simplify

\frac{2 t}{2} = \frac{\frac{3 π}{2}}{2} + \frac{2 πn}{2}

Simplify

\frac{2 t}{2} : t

\frac{2 t}{2}

Divide the numbers:

\frac{2}{2} = 1

= t

Simplify

\frac{\frac{3 π}{2}}{2} + \frac{2 πn}{2} : \frac{3 π}{4} + πn

\frac{\frac{3 π}{2}}{2} + \frac{2 πn}{2}

\frac{\frac{3 π}{2}}{2} = \frac{3 π}{4}

\frac{\frac{3 π}{2}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{3 π}{2 \cdot 2}

Multiply the numbers:

2 \cdot 2 = 4

= \frac{3 π}{4}

\frac{2 πn}{2} = πn

\frac{2 πn}{2}

Divide the numbers:

\frac{2}{2} = 1

= πn

= \frac{3 π}{4} + πn

t = \frac{3 π}{4} + πn

t = \frac{3 π}{4} + πn

t = \frac{3 π}{4} + πn

t = \frac{π}{4} + πn, t = \frac{3 π}{4} + πn

Graph

Popular Examples

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4 cos^{2} (θ) = 3 + 3 sin (θ)

2sin(x)+tan(x)=0

2 sin (x) + tan (x) = 0

arctan(x+1)+arctan(x-1)=arctan(12)

arctan (x + 1) + arctan (x - 1) = arctan (12)

tan^2(x)-3.31tan(x)+1.55=0

tan^{2} (x) - 3.31 tan (x) + 1.55 = 0

2sec(x)+2=6

2 sec (x) + 2 = 6

Frequently Asked Questions (FAQ)

What is the general solution for 2cos(2t)=0 ?
The general solution for 2cos(2t)=0 is t= pi/4+pin,t=(3pi)/4+pin