What is the general solution for 2cos(2t)=0 ?

The general solution for 2cos(2t)=0 is t= pi/4+pin,t=(3pi)/4+pin

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2cos(2t)=0

2 cos (2 t) = 0

t = \frac{π}{4} + πn, t = \frac{3 π}{4} + πn

Solution steps

2 cos (2 t) = 0

Divide both sides by

2

cos (2 t) = 0

General solutions for

cos (2 t) = 0

2 t = \frac{π}{2} + 2 πn, 2 t = \frac{3 π}{2} + 2 πn

Solve

2 t = \frac{π}{2} + 2 πn : t = \frac{π}{4} + πn

Solve

2 t = \frac{3 π}{2} + 2 πn : t = \frac{3 π}{4} + πn

t = \frac{π}{4} + πn, t = \frac{3 π}{4} + πn

4 cos^{2} (θ) = 3 + 3 sin (θ)

4 cos (3 θ) + 23 = 0

cos (2 θ) + 3 cos (θ) - 1 = 0

2 sin^{2} (x) = 2 - 3 cos (x)

2 sin (x) + tan (x) = 0

What is the general solution for 2cos(2t)=0 ?
The general solution for 2cos(2t)=0 is t= pi/4+pin,t=(3pi)/4+pin