What is the general solution for 6cot^2(x)-18=0 ?

The general solution for 6cot^2(x)-18=0 is x= pi/6+pin,x=(5pi)/6+pin

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6cot^2(x)-18=0

6 cot^{2} (x) - 18 = 0

x = \frac{π}{6} + πn, x = \frac{5 π}{6} + πn

Solution steps

6 cot^{2} (x) - 18 = 0

Solve by substitution

cot (x) = 3, cot (x) = - 3

cot (x) = 3 : x = \frac{π}{6} + πn

cot (x) = - 3 : x = \frac{5 π}{6} + πn

Combine all the solutions

x = \frac{π}{6} + πn, x = \frac{5 π}{6} + πn

(2 sin (θ) - 3) (sin (θ) - 1) = 0

20 sin^{2} (x) + cos (x) - 19 = 0

sin^{2} (y) = 1

2 cos (2 θ) + 15 cos (θ) + 5 = 7 cos (θ)

tan^{2} (x) = 2 - tan (x)

What is the general solution for 6cot^2(x)-18=0 ?
The general solution for 6cot^2(x)-18=0 is x= pi/6+pin,x=(5pi)/6+pin