What is the general solution for (sin((2*5+1)*w/2))/(sin(w/2))=0 ?

The general solution for (sin((2*5+1)*w/2))/(sin(w/2))=0 is w=(4pin)/(11),w=(2pi)/(11)+(4pin)/(11)

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(sin((25+1)w/2))/(sin(w/2))=0

\frac{sin ( ( 2 \cdot 5 + 1 ) \cdot \frac{w}{2} )}{sin ( \frac{w}{2} )} = 0

w = \frac{4 πn}{11}, w = \frac{2 π}{11} + \frac{4 πn}{11}

Solution steps

\frac{sin ( ( 2 \cdot 5 + 1 ) \frac{w}{2} )}{sin ( \frac{w}{2} )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

sin ((2 \cdot 5 + 1) \frac{w}{2}) = 0

General solutions for

sin ((25 + 1) \frac{w}{2}) = 0

(25 + 1) \frac{w}{2} = 0 + 2 πn, (25 + 1) \frac{w}{2} = π + 2 πn

Solve

(25 + 1) \frac{w}{2} = 0 + 2 πn : w = \frac{4 πn}{11}

Solve

(25 + 1) \frac{w}{2} = π + 2 πn : w = \frac{2 π}{11} + \frac{4 πn}{11}

w = \frac{4 πn}{11}, w = \frac{2 π}{11} + \frac{4 πn}{11}

sin (θ) = - 0.7

sin (θ) = - 0.1

tan (θ) + 3 = 0, 0 \leq θ \leq 2 π

2 tan (3 x) = 2

4 cot (x) = 11, 0^{\circ} \leq x < 36 0^{\circ}

What is the general solution for (sin((2*5+1)*w/2))/(sin(w/2))=0 ?
The general solution for (sin((2*5+1)*w/2))/(sin(w/2))=0 is w=(4pin)/(11),w=(2pi)/(11)+(4pin)/(11)