What is the general solution for -6cos(A)+8=3cos(A)+8 ?

The general solution for -6cos(A)+8=3cos(A)+8 is A= pi/2+2pin,A=(3pi)/2+2pin

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-6cos(A)+8=3cos(A)+8

- 6 cos (A) + 8 = 3 cos (A) + 8

A = \frac{π}{2} + 2 πn, A = \frac{3 π}{2} + 2 πn

Solution steps

- 6 cos (A) + 8 = 3 cos (A) + 8

Solve by substitution

cos (A) = 0

cos (A) = 0 : A = \frac{π}{2} + 2 πn, A = \frac{3 π}{2} + 2 πn

Combine all the solutions

A = \frac{π}{2} + 2 πn, A = \frac{3 π}{2} + 2 πn

cos (x) - 5 = - 4 - sin (x)

sin (d) = 0.19

2 sin^{2} (4 x) = 1

(sin (x) + cos (x))^{2} = 1 + sin^{2} (x)

x, y = sin (x) y

What is the general solution for -6cos(A)+8=3cos(A)+8 ?
The general solution for -6cos(A)+8=3cos(A)+8 is A= pi/2+2pin,A=(3pi)/2+2pin