What is the general solution for -20sin(4x)=0 ?

The general solution for -20sin(4x)=0 is x=(pin)/2 ,x= pi/4+(pin)/2

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-20sin(4x)=0

- 20 sin (4 x) = 0

x = \frac{πn}{2}, x = \frac{π}{4} + \frac{πn}{2}

Solution steps

- 20 sin (4 x) = 0

Divide both sides by

- 20

sin (4 x) = 0

General solutions for

sin (4 x) = 0

4 x = 0 + 2 πn, 4 x = π + 2 πn

Solve

4 x = 0 + 2 πn : x = \frac{πn}{2}

Solve

4 x = π + 2 πn : x = \frac{π}{4} + \frac{πn}{2}

x = \frac{πn}{2}, x = \frac{π}{4} + \frac{πn}{2}

x, y = 2 sin (\frac{π}{4} x)

cos (3 θ) = - \frac{3}{2}

cot (x) = \frac{12}{5}

sin (x) = \frac{8}{13}

a, f = t sin (a t)

What is the general solution for -20sin(4x)=0 ?
The general solution for -20sin(4x)=0 is x=(pin)/2 ,x= pi/4+(pin)/2