What is the general solution for cos(θ)=1,0<= θ<= 180 ?

The general solution for cos(θ)=1,0<= θ<= 180 is θ=0

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cos(θ)=1,0<= θ<= 180

cos (θ) = 1, 0^{\circ} \leq θ \leq 18 0^{\circ}

θ = 0

Solution steps

cos (θ) = 1, 0^{\circ} \leq θ \leq 18 0^{\circ}

General solutions for

cos (θ) = 1

θ = 0 + 36 0^{\circ} n

Solve

θ = 0 + 36 0^{\circ} n : θ = 36 0^{\circ} n

θ = 36 0^{\circ} n

Solutions for the range

0 \leq θ \leq 18 0^{\circ}

θ = 0

x, z = cos (2 x + y)

16 tan^{2} (x) - 1 = 0

sin^{2} (x) - sin (x) = 0, 0 \leq x \leq 2 π

sin (x + 3 7^{\circ}) = cos (2 x + 8)

sin (θ) = \frac{8}{17}, cos (θ) = \frac{15}{17}

What is the general solution for cos(θ)=1,0<= θ<= 180 ?
The general solution for cos(θ)=1,0<= θ<= 180 is θ=0