What is the general solution for 2sin^2(x)+cos(x)+1=0 ?

The general solution for 2sin^2(x)+cos(x)+1=0 is x=pi+2pin

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2sin^2(x)+cos(x)+1=0

2 sin^{2} (x) + cos (x) + 1 = 0

x = π + 2 πn

Solution steps

2 sin^{2} (x) + cos (x) + 1 = 0

Rewrite using trig identities

3 + cos (x) - 2 cos^{2} (x) = 0

Solve by substitution

cos (x) = - 1, cos (x) = \frac{3}{2}

cos (x) = - 1 : x = π + 2 πn

cos (x) = \frac{3}{2} :

No Solution

Combine all the solutions

x = π + 2 πn

3 tan (2 x) - 3 = 0

t, x = 2 sin (t)

11 - sin (θ) = cos (2 θ)

2 cos^{2} (x) - 5 cos (x) = - 2

- 2 (cos (x) - 3) = 7

What is the general solution for 2sin^2(x)+cos(x)+1=0 ?
The general solution for 2sin^2(x)+cos(x)+1=0 is x=pi+2pin