What is the general solution for sin(t)= 120/500 sin(110) ?

The general solution for sin(t)= 120/500 sin(110) is t=0.22748…+360n,t=180-0.22748…+360n

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sin(t)= 120/500 sin(110)

sin (t) = \frac{120}{500} sin (11 0^{\circ})

t = 0.22748 \dots + 36 0^{\circ} n, t = 18 0^{\circ} - 0.22748 \dots + 36 0^{\circ} n

Solution steps

sin (t) = \frac{120}{500} sin (11 0^{\circ})

Simplify

\frac{120}{500} sin (11 0^{\circ}) : \frac{6 sin ( 11 0 ^{\circ} )}{25}

Apply trig inverse properties

t = arcsin (\frac{6 sin ( 11 0 ^{\circ} )}{25}) + 36 0^{\circ} n, t = 18 0^{\circ} - arcsin (\frac{6 sin ( 11 0 ^{\circ} )}{25}) + 36 0^{\circ} n

Show solutions in decimal form

t = 0.22748 \dots + 36 0^{\circ} n, t = 18 0^{\circ} - 0.22748 \dots + 36 0^{\circ} n

tan (θ) + 1 = 3 + 3 cot (θ)

2 - 2 cos^{2} (x) = 2 cos^{2} (\frac{x}{2})

3 = 4 sin (8 (- \frac{π}{2} - x)) + 3

5 sin (x) - 7 = 0

tan (\frac{θ}{2} + \frac{π}{4}) = - 1, 0 \leq θ \leq 2 π

What is the general solution for sin(t)= 120/500 sin(110) ?
The general solution for sin(t)= 120/500 sin(110) is t=0.22748…+360n,t=180-0.22748…+360n