What is the general solution for sin^2((2x)/3)-1=0 ?

The general solution for sin^2((2x)/3)-1=0 is x=(3pi)/4+3pin,x=(9pi)/4+3pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin^2((2x)/3)-1=0

sin^{2} (\frac{2 x}{3}) - 1 = 0

x = \frac{3 π}{4} + 3 πn, x = \frac{9 π}{4} + 3 πn

Solution steps

sin^{2} (\frac{2 x}{3}) - 1 = 0

Solve by substitution

sin (\frac{2 x}{3}) = 1, sin (\frac{2 x}{3}) = - 1

sin (\frac{2 x}{3}) = 1 : x = \frac{3 π}{4} + 3 πn

sin (\frac{2 x}{3}) = - 1 : x = \frac{9 π}{4} + 3 πn

Combine all the solutions

x = \frac{3 π}{4} + 3 πn, x = \frac{9 π}{4} + 3 πn

5 sin (x) = 2 + sin (x)

- 3 = 4 - 2 arctan (\frac{4 - 2 - C}{4 - C})

cos^{2} (x) + \frac{11}{2} cos (x) = 3 cos (x) - 1

23 sin (4 θ) = 3

3 tan (3 x) = 3

What is the general solution for sin^2((2x)/3)-1=0 ?
The general solution for sin^2((2x)/3)-1=0 is x=(3pi)/4+3pin,x=(9pi)/4+3pin