What is the general solution for 0=2sin(θ)+sqrt(3) ?

The general solution for 0=2sin(θ)+sqrt(3) is θ=(4pi)/3+2pin,θ=(5pi)/3+2pin

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0=2sin(θ)+sqrt(3)

0 = 2 sin (θ) + 3

θ = \frac{4 π}{3} + 2 πn, θ = \frac{5 π}{3} + 2 πn

Solution steps

0 = 2 sin (θ) + 3

Switch sides

2 sin (θ) + 3 = 0

Move

3

to the right side

2 sin (θ) = - 3

Divide both sides by

2

sin (θ) = - \frac{3}{2}

General solutions for

sin (θ) = - \frac{3}{2}

θ = \frac{4 π}{3} + 2 πn, θ = \frac{5 π}{3} + 2 πn

8 sec^{2} (x) - 8 sec (x) = 16

50 = 36 sin (\frac{2 π}{365} (t - 101)) + 14

\frac{sin ( x ^{\circ} )}{53} = \frac{sin ( 7 6 ^{\circ} )}{50}

sec (θ) + tan (θ) = 1

x, 2 cos^{2} (x) = 1

What is the general solution for 0=2sin(θ)+sqrt(3) ?
The general solution for 0=2sin(θ)+sqrt(3) is θ=(4pi)/3+2pin,θ=(5pi)/3+2pin