What is the general solution for 50=36sin((2pi)/(365)(t-101))+14 ?

The general solution for 50=36sin((2pi)/(365)(t-101))+14 is t=365n+769/4

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50=36sin((2pi)/(365)(t-101))+14

50 = 36 sin (\frac{2 π}{365} (t - 101)) + 14

t = 365 n + \frac{769}{4}

Solution steps

50 = 36 sin (\frac{2 π}{365} (t - 101)) + 14

Switch sides

36 sin (\frac{2 π}{365} (t - 101)) + 14 = 50

Move

14

to the right side

36 sin (\frac{2 π}{365} (t - 101)) = 36

Divide both sides by

36

sin (\frac{2 π}{365} (t - 101)) = 1

General solutions for

sin (\frac{2 π}{365} (t - 101)) = 1

\frac{2 π}{365} (t - 101) = \frac{π}{2} + 2 πn

Solve

\frac{2 π}{365} (t - 101) = \frac{π}{2} + 2 πn : t = 365 n + \frac{769}{4}

t = 365 n + \frac{769}{4}

\frac{sin ( x ^{\circ} )}{53} = \frac{sin ( 7 6 ^{\circ} )}{50}

sec (θ) + tan (θ) = 1

x, 2 cos^{2} (x) = 1

sin (2 θ - \frac{π}{3}) = - \frac{1}{2}

sec (x) + cos (x) = sin (x) tan (x)

What is the general solution for 50=36sin((2pi)/(365)(t-101))+14 ?
The general solution for 50=36sin((2pi)/(365)(t-101))+14 is t=365n+769/4