What is the general solution for cos(2x)=0.28 ?

The general solution for cos(2x)=0.28 is x=(1.28700…)/2+pin,x=pi-(1.28700…)/2+pin

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cos(2x)=0.28

cos (2 x) = 0.28

x = \frac{1.28700 \dots}{2} + πn, x = π - \frac{1.28700 \dots}{2} + πn

Solution steps

cos (2 x) = 0.28

Apply trig inverse properties

2 x = arccos (0.28) + 2 πn, 2 x = 2 π - arccos (0.28) + 2 πn

Solve

2 x = arccos (0.28) + 2 πn : x = \frac{arccos ( 0.28 )}{2} + πn

Solve

2 x = 2 π - arccos (0.28) + 2 πn : x = π - \frac{arccos ( 0.28 )}{2} + πn

x = \frac{arccos ( 0.28 )}{2} + πn, x = π - \frac{arccos ( 0.28 )}{2} + πn

Show solutions in decimal form

x = \frac{1.28700 \dots}{2} + πn, x = π - \frac{1.28700 \dots}{2} + πn

cos (3 x) = 3 sin (3 x)

- 3 cos (2 x) = 0

csc (x) + 1 = 0, 0 \leq x < 2 π

15 cos (x) = 7 + cos (x)

sec (x) = 1 - tan^{2} (x)

What is the general solution for cos(2x)=0.28 ?
The general solution for cos(2x)=0.28 is x=(1.28700…)/2+pin,x=pi-(1.28700…)/2+pin