What is the general solution for r=2acos(x) ?

The general solution for r=2acos(x) is x=arccos(r/(2a))+2pin,x=-arccos(r/(2a))+2pin

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r=2acos(x)

r = 2 a cos (x)

x = arccos (\frac{r}{2 a}) + 2 πn, x = - arccos (\frac{r}{2 a}) + 2 πn

Solution steps

r = 2 a cos (x)

Switch sides

2 a cos (x) = r

Divide both sides by

2 a; a \neq = 0

cos (x) = \frac{r}{2 a}; a \neq = 0

Apply trig inverse properties

x = arccos (\frac{r}{2 a}) + 2 πn, x = - arccos (\frac{r}{2 a}) + 2 πn

tan (t) = - \frac{1}{3}, - π < t \leq π

sin (x) = \frac{- 4}{5}

16 = 7 - 7 cos (θ)

sin (θ) = \frac{5}{4}

2 cos (x) + 2 = 0

What is the general solution for r=2acos(x) ?
The general solution for r=2acos(x) is x=arccos(r/(2a))+2pin,x=-arccos(r/(2a))+2pin