What is the general solution for sin(x)-9=cos(x)-9 ?

The general solution for sin(x)-9=cos(x)-9 is x= pi/4+pin

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sin(x)-9=cos(x)-9

sin (x) - 9 = cos (x) - 9

x = \frac{π}{4} + πn

Solution steps

sin (x) - 9 = cos (x) - 9

Subtract

cos (x) - 9

from both sides

sin (x) - cos (x) = 0

Rewrite using trig identities

tan (x) - 1 = 0

Move

1

to the right side

tan (x) = 1

General solutions for

tan (x) = 1

x = \frac{π}{4} + πn

7 sin (x) + 1 = 5 sin (x)

sec (x) + tan (x) = 1, (0, 2 π)

cos^{2} (θ) - cos (θ) - 20 = 0

100.0191 = 180 - arctan (\frac{3.9254}{0.6936 - x})

- 9 sin (x) = 0

What is the general solution for sin(x)-9=cos(x)-9 ?
The general solution for sin(x)-9=cos(x)-9 is x= pi/4+pin