What is the general solution for 2sin^2(x)+sqrt(2)sin(x)=0 ?

The general solution for 2sin^2(x)+sqrt(2)sin(x)=0 is x=2pin,x=pi+2pin,x=(5pi)/4+2pin,x=(7pi)/4+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2sin^2(x)+sqrt(2)sin(x)=0

2 sin^{2} (x) + 2 sin (x) = 0

x = 2 πn, x = π + 2 πn, x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

Solution steps

2 sin^{2} (x) + 2 sin (x) = 0

Solve by substitution

sin (x) = 0, sin (x) = - \frac{2}{2}

sin (x) = 0 : x = 2 πn, x = π + 2 πn

sin (x) = - \frac{2}{2} : x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

Combine all the solutions

x = 2 πn, x = π + 2 πn, x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

8 sin (x) cos (x) = 0

cos (θ) = \frac{9}{41}

3 cos (2 t) + 4 = 1, 0 \leq t \leq π

cos (2 θ) - 5 = - 9 sin (θ)

cos (x) = \frac{13}{19}

What is the general solution for 2sin^2(x)+sqrt(2)sin(x)=0 ?
The general solution for 2sin^2(x)+sqrt(2)sin(x)=0 is x=2pin,x=pi+2pin,x=(5pi)/4+2pin,x=(7pi)/4+2pin