What is the general solution for cos(θ)= 9/41 ?

The general solution for cos(θ)= 9/41 is θ=1.34948…+2pin,θ=2pi-1.34948…+2pin

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cos(θ)= 9/41

cos (θ) = \frac{9}{41}

θ = 1.34948 \dots + 2 πn, θ = 2 π - 1.34948 \dots + 2 πn

Solution steps

cos (θ) = \frac{9}{41}

Apply trig inverse properties

θ = arccos (\frac{9}{41}) + 2 πn, θ = 2 π - arccos (\frac{9}{41}) + 2 πn

Show solutions in decimal form

θ = 1.34948 \dots + 2 πn, θ = 2 π - 1.34948 \dots + 2 πn

3 cos (2 t) + 4 = 1, 0 \leq t \leq π

cos (2 θ) - 5 = - 9 sin (θ)

cos (x) = \frac{13}{19}

0 = 3 cos (2 x)

sin^{2} (x) - 9 cos (x) + 9 = 0

What is the general solution for cos(θ)= 9/41 ?
The general solution for cos(θ)= 9/41 is θ=1.34948…+2pin,θ=2pi-1.34948…+2pin