What is the general solution for 0=3cos(2x) ?

The general solution for 0=3cos(2x) is x= pi/4+pin,x=(3pi)/4+pin

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0=3cos(2x)

0 = 3 cos (2 x)

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

Solution steps

0 = 3 cos (2 x)

Switch sides

3 cos (2 x) = 0

Divide both sides by

3

cos (2 x) = 0

General solutions for

cos (2 x) = 0

2 x = \frac{π}{2} + 2 πn, 2 x = \frac{3 π}{2} + 2 πn

Solve

2 x = \frac{π}{2} + 2 πn : x = \frac{π}{4} + πn

Solve

2 x = \frac{3 π}{2} + 2 πn : x = \frac{3 π}{4} + πn

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

sin^{2} (x) - 9 cos (x) + 9 = 0

sinh (x) = \frac{8}{15}

cos (x) = \frac{13}{16}

tan^{2} (x) - 4 tan (x) + 3 = 0

sin (x) + sin (3 x) = cos (x)

What is the general solution for 0=3cos(2x) ?
The general solution for 0=3cos(2x) is x= pi/4+pin,x=(3pi)/4+pin