What is the general solution for cos(x)(2cos(x)-3)=0 ?

The general solution for cos(x)(2cos(x)-3)=0 is x= pi/2+2pin,x=(3pi)/2+2pin

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cos(x)(2cos(x)-3)=0

cos (x) (2 cos (x) - 3) = 0

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

Solution steps

cos (x) (2 cos (x) - 3) = 0

Solving each part separately

cos (x) = 0 or 2 cos (x) - 3 = 0

cos (x) = 0 : x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

2 cos (x) - 3 = 0 :

No Solution

Combine all the solutions

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

cos (θ) = (\frac{sin ( 6 0 ^{\circ} )}{1.28})

4 cos^{2} (x) - 3 cos (x) - 1 = 0

2 sin^{2} (\frac{x}{3}) = 1

cos (2 x) = 3 - 5 sin (x)

4 cos^{2} (x) + 43 sin (x) = 7

What is the general solution for cos(x)(2cos(x)-3)=0 ?
The general solution for cos(x)(2cos(x)-3)=0 is x= pi/2+2pin,x=(3pi)/2+2pin