Is (1+sin(θ))/(cos(θ))=sec(θ)+tan(θ) ?

The answer to whether (1+sin(θ))/(cos(θ))=sec(θ)+tan(θ) is True

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prove (1+sin(θ))/(cos(θ))=sec(θ)+tan(θ)

prove

\frac{1 + sin ( θ )}{cos ( θ )} = sec (θ) + tan (θ)

True

Solution steps

\frac{1 + sin ( θ )}{cos ( θ )} = sec (θ) + tan (θ)

Manipulating right side

sec (θ) + tan (θ)

Express with sin, cos

= \frac{1 + sin ( θ )}{cos ( θ )}

We showed that the two sides could take the same form

\Rightarrow True

(sec^{2} (x) - 1) cos (x) = tan (x) sin (x)

1 - \frac{sin ^{2} ( θ )}{1 - cos ( θ )} = - cos (θ)

(1 - sin^{2} (x)) tan (x) = cos (x) sin (x)

cot (x) = \frac{1}{tan ( x )}

(1 - cos (θ)) (1 + cos (θ)) = \frac{1}{csc ^{2} ( θ )}

Is (1+sin(θ))/(cos(θ))=sec(θ)+tan(θ) ?
The answer to whether (1+sin(θ))/(cos(θ))=sec(θ)+tan(θ) is True