Is sec(θ)+tan(θ)=(cos(θ))/(1-sin(θ)) ?

The answer to whether sec(θ)+tan(θ)=(cos(θ))/(1-sin(θ)) is True

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prove sec(θ)+tan(θ)=(cos(θ))/(1-sin(θ))

prove

sec (θ) + tan (θ) = \frac{cos ( θ )}{1 - sin ( θ )}

True

Solution steps

sec (θ) + tan (θ) = \frac{cos ( θ )}{1 - sin ( θ )}

Manipulating left side

sec (θ) + tan (θ)

Express with sin, cos

= \frac{1 + sin ( θ )}{cos ( θ )}

Rewrite using trig identities

= \frac{cos ( θ )}{1 - sin ( θ )}

We showed that the two sides could take the same form

\Rightarrow True

sin^{2} (x) - 3 cos^{2} (x) = 4 sin^{2} (x) - 3

tan^{2} (x) + 6 = sec^{2} (x) + 5

tan (\frac{π}{2} - θ) tan (θ) = 1

(1 - sin^{2} (x)) csc^{2} (x) = cot^{2} (x)

sin (t) tan (t) = \frac{1 - cos ^{2} ( t )}{cos ( t )}

Is sec(θ)+tan(θ)=(cos(θ))/(1-sin(θ)) ?
The answer to whether sec(θ)+tan(θ)=(cos(θ))/(1-sin(θ)) is True