Is sin^2(x)-3cos^2(x)=4sin^2(x)-3 ?

The answer to whether sin^2(x)-3cos^2(x)=4sin^2(x)-3 is True

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prove sin^2(x)-3cos^2(x)=4sin^2(x)-3

prove

sin^{2} (x) - 3 cos^{2} (x) = 4 sin^{2} (x) - 3

True

Solution steps

sin^{2} (x) - 3 cos^{2} (x) = 4 sin^{2} (x) - 3

Manipulating left side

sin^{2} (x) - 3 cos^{2} (x)

Rewrite using trig identities

= 4 sin^{2} (x) - 3

We showed that the two sides could take the same form

\Rightarrow True

tan^{2} (x) + 6 = sec^{2} (x) + 5

tan (\frac{π}{2} - θ) tan (θ) = 1

(1 - sin^{2} (x)) csc^{2} (x) = cot^{2} (x)

sin (t) tan (t) = \frac{1 - cos ^{2} ( t )}{cos ( t )}

\frac{sin ^{2} ( θ )}{cos ( θ )} = sec (θ) - cos (θ)

Is sin^2(x)-3cos^2(x)=4sin^2(x)-3 ?
The answer to whether sin^2(x)-3cos^2(x)=4sin^2(x)-3 is True