Is (1+csc(θ))/(sec(θ))-cot(θ)=cos(θ) ?

The answer to whether (1+csc(θ))/(sec(θ))-cot(θ)=cos(θ) is True

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prove (1+csc(θ))/(sec(θ))-cot(θ)=cos(θ)

prove

\frac{1 + csc ( θ )}{sec ( θ )} - cot (θ) = cos (θ)

True

Solution steps

\frac{1 + csc ( θ )}{sec ( θ )} - cot (θ) = cos (θ)

Manipulating left side

\frac{1 + csc ( θ )}{sec ( θ )} - cot (θ)

Express with sin, cos

= cos (θ)

We showed that the two sides could take the same form

\Rightarrow True

sin (2 θ) = \frac{2 cot ( θ )}{1 + cot ^{2} ( θ )}

cos (A) csc (A) = cot (A)

tan (θ) = \frac{1 - cos ( 2 θ )}{sin ( 2 θ )}

cos^{2} (x) = sin^{2} (x) cos^{2} (x) + cos^{4} (x)

\frac{sin ^{2} ( x ) cot ( x )}{cos ( x )} = sin (x)

Is (1+csc(θ))/(sec(θ))-cot(θ)=cos(θ) ?
The answer to whether (1+csc(θ))/(sec(θ))-cot(θ)=cos(θ) is True