Is sin(θ)=(tan(θ))/(sec(θ)) ?

The answer to whether sin(θ)=(tan(θ))/(sec(θ)) is True

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prove sin(θ)=(tan(θ))/(sec(θ))

prove

sin (θ) = \frac{tan ( θ )}{sec ( θ )}

True

Solution steps

sin (θ) = \frac{tan ( θ )}{sec ( θ )}

Manipulating right side

\frac{tan ( θ )}{sec ( θ )}

Express with sin, cos

= sin (θ)

We showed that the two sides could take the same form

\Rightarrow True

\frac{sec ( y )}{tan ( y ) + cot ( y )} = sin (y)

\frac{sin ^{2} ( θ )}{( 1 - cos ( θ ) )} = 1 + cos (θ)

cot (x) tan (x) = sec (x) csc (x)

\frac{1}{csc ( x ) - sin ( x )} = tan (x) sec (x)

sec^{4} (θ) - tan^{4} (θ) = 1 + 2 tan^{2} (θ)

Is sin(θ)=(tan(θ))/(sec(θ)) ?
The answer to whether sin(θ)=(tan(θ))/(sec(θ)) is True