Is 8cos^2(x)-8sin^2(x)=8-16sin^2(x) ?

The answer to whether 8cos^2(x)-8sin^2(x)=8-16sin^2(x) is True

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prove 8cos^2(x)-8sin^2(x)=8-16sin^2(x)

prove

8 cos^{2} (x) - 8 sin^{2} (x) = 8 - 16 sin^{2} (x)

True

Solution steps

8 cos^{2} (x) - 8 sin^{2} (x) = 8 - 16 sin^{2} (x)

Manipulating left side

8 cos^{2} (x) - 8 sin^{2} (x)

Rewrite using trig identities

= 8 - 16 sin^{2} (x)

We showed that the two sides could take the same form

\Rightarrow True

\frac{sec ( x ) csc ( x )}{cot ( x )} = sec^{2} (x)

(sin (θ) - cos (θ))^{2} = 1 - 2 sin (θ) cos (θ)

cot (θ) sin (θ) sec (θ) = 1

cos^{4} (x) = 1 - 2 sin^{2} (x) + sin^{4} (x)

tan (x) \cdot cos (x) = sin (x)

Is 8cos^2(x)-8sin^2(x)=8-16sin^2(x) ?
The answer to whether 8cos^2(x)-8sin^2(x)=8-16sin^2(x) is True