Is (csc(θ)sin(θ))/(sec(θ))=cos(θ) ?

The answer to whether (csc(θ)sin(θ))/(sec(θ))=cos(θ) is True

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prove (csc(θ)sin(θ))/(sec(θ))=cos(θ)

prove

\frac{csc ( θ ) sin ( θ )}{sec ( θ )} = cos (θ)

True

Solution steps

\frac{csc ( θ ) sin ( θ )}{sec ( θ )} = cos (θ)

Manipulating left side

\frac{csc ( θ ) sin ( θ )}{sec ( θ )}

Express with sin, cos

= cos (θ)

We showed that the two sides could take the same form

\Rightarrow True

tan (x) cot (x) - sin^{2} (x) = cos^{2} (x)

sin (x) - sin (x) \cdot cos^{2} (x) = sin^{3} (x)

cos^{2} (B) - sin^{2} (B) = 1 - 2 sin^{2} (B)

cot (u) tan (u) - cos^{2} (u) = sin^{2} (u)

\frac{csc ^{4} ( x ) - 1}{cot ^{2} ( x )} = csc^{2} (x) + 1

Is (csc(θ)sin(θ))/(sec(θ))=cos(θ) ?
The answer to whether (csc(θ)sin(θ))/(sec(θ))=cos(θ) is True