Is sin(a+b)sin(a-b)=sin^2(b)-sin^2(a) ?

The answer to whether sin(a+b)sin(a-b)=sin^2(b)-sin^2(a) is False

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prove sin(a+b)sin(a-b)=sin^2(b)-sin^2(a)

prove

sin (a + b) sin (a - b) = sin^{2} (b) - sin^{2} (a)

False

Solution steps

sin (a + b) sin (a - b) = sin^{2} (b) - sin^{2} (a)

Show that the two sides are not equal

\Rightarrow False

\frac{tan ( x ) + cot ( x )}{tan ( x )} = csc^{2} (x)

tan (x - \frac{π}{4}) = \frac{tan ( x ) - 1}{tan ( x ) + 1}

1 - csc^{2} (x) tan^{2} (x) = - tan^{2} (x)

sec (b) + tan (b) = \frac{cos ( b )}{1 - sin ( b )}

cot^{4} (x) + cot^{2} (x) = csc^{4} (x) - csc^{2} (x)

Is sin(a+b)sin(a-b)=sin^2(b)-sin^2(a) ?
The answer to whether sin(a+b)sin(a-b)=sin^2(b)-sin^2(a) is False