Is sec^2(x)-sin^2(x)sec^2(x)=1 ?

The answer to whether sec^2(x)-sin^2(x)sec^2(x)=1 is True

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prove sec^2(x)-sin^2(x)sec^2(x)=1

prove

sec^{2} (x) - sin^{2} (x) sec^{2} (x) = 1

True

Solution steps

sec^{2} (x) - sin^{2} (x) sec^{2} (x) = 1

Manipulating left side

sec^{2} (x) - sin^{2} (x) sec^{2} (x)

Express with sin, cos

= \frac{1 - sin ^{2} ( x )}{cos ^{2} ( x )}

Rewrite using trig identities

= 1

We showed that the two sides could take the same form

\Rightarrow True

tan (2 a) - 2 tan (2 a) sin^{2} (a) = sin (2 a)

tan (t) sin (t) = \frac{sec ^{2} ( t ) - 1}{sec ( t )}

2 cos^{2} (x) = 1 + cos (2 x)

80 = arcsin (45.6443 \cdot \frac{sin ( c )}{35})

\frac{( tan ^{2} ( x ) )}{sec ( x )} = sin (x) tan (x)

Is sec^2(x)-sin^2(x)sec^2(x)=1 ?
The answer to whether sec^2(x)-sin^2(x)sec^2(x)=1 is True