Is cot^2(α)+1= 1/(sin^2(α)) ?

The answer to whether cot^2(α)+1= 1/(sin^2(α)) is True

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prove cot^2(α)+1= 1/(sin^2(α))

prove

cot^{2} (α) + 1 = \frac{1}{sin ^{2} ( α )}

True

Solution steps

cot^{2} (α) + 1 = \frac{1}{sin ^{2} ( α )}

Manipulating left side

cot^{2} (α) + 1

Express with sin, cos

1 + cot^{2} (α)

Use the basic trigonometric identity:

cot (x) = \frac{cos ( x )}{sin ( x )}

= 1 + (\frac{cos ( α )}{sin ( α )})^{2}

Simplify

1 + (\frac{cos ( α )}{sin ( α )})^{2} : \frac{sin ^{2} ( α ) + cos ^{2} ( α )}{sin ^{2} ( α )}

1 + (\frac{cos ( α )}{sin ( α )})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= 1 + \frac{cos ^{2} ( α )}{sin ^{2} ( α )}

Convert element to fraction:

1 = \frac{1 sin ^{2} ( α )}{sin ^{2} ( α )}

= \frac{1 \cdot sin ^{2} ( α )}{sin ^{2} ( α )} + \frac{cos ^{2} ( α )}{sin ^{2} ( α )}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot sin ^{2} ( α ) + cos ^{2} ( α )}{sin ^{2} ( α )}

Multiply:

1 \cdot sin^{2} (α) = sin^{2} (α)

= \frac{sin ^{2} ( α ) + cos ^{2} ( α )}{sin ^{2} ( α )}

= \frac{sin ^{2} ( α ) + cos ^{2} ( α )}{sin ^{2} ( α )}

= \frac{cos ^{2} ( α ) + sin ^{2} ( α )}{sin ^{2} ( α )}

Rewrite using trig identities

\frac{cos ^{2} ( α ) + sin ^{2} ( α )}{sin ^{2} ( α )}

Use the Pythagorean identity:

cos^{2} (x) + sin^{2} (x) = 1

= \frac{1}{sin ^{2} ( α )}

= \frac{1}{sin ^{2} ( α )}

We showed that the two sides could take the same form

\Rightarrow True

sin (3 x) = 3 sin (x) cos^{2} (x) - sin^{3} (x)

\frac{cot ( x ) + tan ( x )}{sec ( x )} = csc (x)

\frac{cos ( 3 x ) - cos ( 5 x )}{sin ( 3 x ) + sin ( 5 x )} = tan (x)

(1 + tan^{2} (x)) cos^{2} (x) = 1

\frac{1 - sin ( θ )}{cos ( θ )} = sec (θ) - tan (θ)

Is cot^2(α)+1= 1/(sin^2(α)) ?
The answer to whether cot^2(α)+1= 1/(sin^2(α)) is True