Is (1-sin(θ))/(cos(θ))=sec(θ)-tan(θ) ?

The answer to whether (1-sin(θ))/(cos(θ))=sec(θ)-tan(θ) is True

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prove (1-sin(θ))/(cos(θ))=sec(θ)-tan(θ)

prove

\frac{1 - sin ( θ )}{cos ( θ )} = sec (θ) - tan (θ)

True

Solution steps

\frac{1 - sin ( θ )}{cos ( θ )} = sec (θ) - tan (θ)

Manipulating right side

sec (θ) - tan (θ)

Express with sin, cos

= \frac{1 - sin ( θ )}{cos ( θ )}

We showed that the two sides could take the same form

\Rightarrow True

cos^{2} (x) = \frac{1}{2} + \frac{1}{2} cos (2 x)

tan (\frac{θ}{2}) = \frac{1 - cos ( θ )}{sin ( θ )}

cot (\frac{1}{x}) = \frac{cos ( \frac{1}{x} )}{sin ( \frac{1}{x} )}

\frac{1 + cos ( 4 x )}{2} = cos^{2} (2 x)

\frac{1}{2 cos ( x ) sin ( x )} = csc (2 x)

Is (1-sin(θ))/(cos(θ))=sec(θ)-tan(θ) ?
The answer to whether (1-sin(θ))/(cos(θ))=sec(θ)-tan(θ) is True