Is tan^2(θ)csc^2(θ)=sec^2(θ) ?

The answer to whether tan^2(θ)csc^2(θ)=sec^2(θ) is True

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prove tan^2(θ)csc^2(θ)=sec^2(θ)

prove

tan^{2} (θ) csc^{2} (θ) = sec^{2} (θ)

True

Solution steps

tan^{2} (θ) csc^{2} (θ) = sec^{2} (θ)

Manipulating left side

tan^{2} (θ) csc^{2} (θ)

Express with sin, cos

= \frac{1}{cos ^{2} ( θ )}

Rewrite using trig identities

sec^{2} (θ)

We showed that the two sides could take the same form

\Rightarrow True

(tan (x) + cot (x))^{2} = sec^{4} (x) cot^{2} (x)

(1 + tan^{2} (s)) (1 - sin^{2} (s)) = 1

8 - 4 csc^{2} (z) = 4 - 4 cot^{2} (z)

1 + sin^{2} (x) = 2 - cos^{2} (x)

\frac{csc ( x ) - sin ( x )}{csc ( x )} = cos^{2} (x)

Is tan^2(θ)csc^2(θ)=sec^2(θ) ?
The answer to whether tan^2(θ)csc^2(θ)=sec^2(θ) is True