Is sin^2(2x)=(1-cos(4x))/2 ?

The answer to whether sin^2(2x)=(1-cos(4x))/2 is True

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prove sin^2(2x)=(1-cos(4x))/2

prove

sin^{2} (2 x) = \frac{1 - cos ( 4 x )}{2}

True

Solution steps

sin^{2} (2 x) = \frac{1 - cos ( 4 x )}{2}

Manipulating right side

\frac{1 - cos ( 4 x )}{2}

Rewrite using trig identities

= sin^{2} (2 x)

We showed that the two sides could take the same form

\Rightarrow True

cot (2 θ) = \frac{csc ( θ ) - 2 sin ( θ )}{2 cos ( θ )}

sin^{2} (θ) sec^{2} (θ) csc^{2} (θ) = sec^{2} (θ)

\frac{csc ( θ ) - sin ( θ )}{sin ( θ )} = cot^{2} (θ)

\frac{csc ^{2} ( x )}{cot ( x )} = sec (x) csc (x)

csc (x) sin (x) = 1

Is sin^2(2x)=(1-cos(4x))/2 ?
The answer to whether sin^2(2x)=(1-cos(4x))/2 is True