Is 1/(sin(θ)cos(θ))=sec(θ)csc(θ) ?

The answer to whether 1/(sin(θ)cos(θ))=sec(θ)csc(θ) is True

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prove 1/(sin(θ)cos(θ))=sec(θ)csc(θ)

prove

\frac{1}{sin ( θ ) cos ( θ )} = sec (θ) csc (θ)

True

Solution steps

\frac{1}{sin ( θ ) cos ( θ )} = sec (θ) csc (θ)

Manipulating right side

sec (θ) csc (θ)

Express with sin, cos

= \frac{1}{cos ( θ ) sin ( θ )}

= \frac{1}{sin ( θ ) cos ( θ )}

We showed that the two sides could take the same form

\Rightarrow True

\frac{2 tan ( x )}{1 - tan ^{2} ( x )} = tan (2 x)

sec (x) \frac{tan ( x )}{sin ( x )} = sec^{2} (x)

\frac{1 + tan ^{2} ( θ )}{csc ^{2} ( θ )} = tan^{2} (θ)

\frac{cos ( x )}{1 - sin ( x )} = sec (x) tan (x)

sin (3 θ) + sin (θ) = 2 sin (θ) cos (θ)

Is 1/(sin(θ)cos(θ))=sec(θ)csc(θ) ?
The answer to whether 1/(sin(θ)cos(θ))=sec(θ)csc(θ) is True