Is sin(θ)cos(θ)cot(θ)+sin^2(θ)=1 ?

The answer to whether sin(θ)cos(θ)cot(θ)+sin^2(θ)=1 is True

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prove sin(θ)cos(θ)cot(θ)+sin^2(θ)=1

prove

sin (θ) cos (θ) cot (θ) + sin^{2} (θ) = 1

True

Solution steps

sin (θ) cos (θ) cot (θ) + sin^{2} (θ) = 1

Manipulating left side

sin (θ) cos (θ) cot (θ) + sin^{2} (θ)

Express with sin, cos

= cos^{2} (θ) + sin^{2} (θ)

Rewrite using trig identities

= 1

We showed that the two sides could take the same form

\Rightarrow True

1 + sec (θ) sin (θ) tan (θ) = sec^{2} (θ)

\frac{sin ( 2 α )}{1 + cos ( 2 α )} = tan (α)

cos (t) + tan (t) sin (t) = sec (t)

\frac{1 - cos ( x )}{- 1 + \frac{1}{c o s ( x )}} = cos (x)

cos^{4} (x) - sin^{4} (x) = tan^{2} (x)

Is sin(θ)cos(θ)cot(θ)+sin^2(θ)=1 ?
The answer to whether sin(θ)cos(θ)cot(θ)+sin^2(θ)=1 is True