Is 1+sin(θ)=csc(θ) ?

The answer to whether 1+sin(θ)=csc(θ) is False

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prove 1+sin(θ)=csc(θ)

prove

1 + sin (θ) = csc (θ)

False

Solution steps

1 + sin (θ) = csc (θ)

Show that the two sides are not equal

\Rightarrow False

\frac{1 + sin ( x )}{1 - sin ( x )} - \frac{1 - sin ( x )}{1 + sin ( x )} = \frac{4 tan ( x )}{cos ( x )}

sin (3 x) = 4 sin (x) \cdot cos^{2} (x) - sin (x)

sin (θ) = \frac{4}{3} sin^{3} (θ) + \frac{1}{3} sin^{3} (θ)

sin (x - \frac{3 π}{2}) + sin (\frac{π}{2} + x) = 2 cos (x)

\frac{1}{cos ( x ) \cdot sin ( x )} - tan (x) = cot (x)