Is sec(a)-cos(a)csc(a)-sin(a)=tan(3a) ?

The answer to whether sec(a)-cos(a)csc(a)-sin(a)=tan(3a) is False

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prove sec(a)-cos(a)csc(a)-sin(a)=tan(3a)

prove

sec (a) - cos (a) csc (a) - sin (a) = tan (3 a)

False

Solution steps

sec (a) - cos (a) csc (a) - sin (a) = tan (3 a)

Show that the two sides are not equal

For

sec (a) - cos (a) csc (a) - sin (a) = tan (3 a)

plug in

a = 1

sec (1) - cos (1) csc (1) - sin (1) = 0.36725 \dots

sec (1) - cos (1) csc (1) - sin (1)

Refine to a decimal form

= 0.36725 \dots

tan (3 \cdot 1) = - 0.14254 \dots

tan (3 \cdot 1)

Refine to a decimal form

= - 0.14254 \dots

The two sides are not equal

\Rightarrow False

cos^{2} (x) = sin (x)

1 - \frac{cos ^{2} ( u )}{1 - sin ( u )} = - sin (u)

tan (θ) (cot (θ) cos (θ) + sin (θ)) = sec (θ)

2 (1 - sin^{2} (x)) = cos (2 x) + 1

sin^{2} (t) = \frac{1 - cos ( 2 t )}{2}

Is sec(a)-cos(a)csc(a)-sin(a)=tan(3a) ?
The answer to whether sec(a)-cos(a)csc(a)-sin(a)=tan(3a) is False